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<  Erlang  ~  Calculate difference between two adjacent list elements

niglas
Posted: Wed Feb 02, 2011 2:21 pm Reply with quote
User Joined: 31 Jan 2011 Posts: 12
How do I calculate the difference of two adjacent sublists?

From:
Code:

[[51,"one"],
 [55,"two"],
 [57,"three"]]

To:
Code:

[[0,"one"],
 [4,"two"],
 [2,"three"]]
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zajda
Posted: Wed Feb 02, 2011 8:26 pm Reply with quote
User Joined: 22 Aug 2009 Posts: 83
This is without std lib, however it would be possible to use mapfoldl.

Code:
-module(xxx).
-export([diff/3, diff/1]).

diff(Input) ->
     diff(Input, 0, []).

diff([[CurrentX, CurrentVal]|Tail], 0, []) ->
    diff(Tail, CurrentX, [[0, CurrentVal]]);
diff([], _PrevX, Acc) ->
    lists:reverse(Acc);
diff([[CurrentX, CurrentVal]|Tail], PrevX, Acc) ->
    diff(Tail, CurrentX, [[CurrentX - PrevX, CurrentVal]|Acc]).
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koops.j@gmail.com
Posted: Thu Feb 03, 2011 12:02 pm Reply with quote
User Joined: 31 Jan 2009 Posts: 12
As suggested by zajda, a solution using lists:mapfoldl/3:

Code:

diff(L) ->
  { Result, _ } =
    lists:mapfoldl(fun([ C, T ], nil) -> { [ 0, T ], C };
                      ([C, T], Prev) -> { [ C-Prev, T ], C }
                   end, nil, L),
  Result.
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niglas
Posted: Fri Feb 04, 2011 9:00 am Reply with quote
User Joined: 31 Jan 2011 Posts: 12
Thanks for the all help.

I'm facing another similar problem too. It seems a little bit more tricky because it requires look ahead instead:

From:
Code:

[[51,"one"],
 [55,"two"],
 [57,"three"]]

To:
Code:

[[4,"one"],
 [2,"two"],
 [0,"three"]]

My first thought is that it could be achieved by reversing the list before putting it into the list, but is there a better way?
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rvirding
Posted: Sat Feb 05, 2011 5:41 pm Reply with quote
User Joined: 30 Aug 2006 Posts: 452 Location: Stockholm, Sweden
You need to do some lookahead here:
Code:
diff ([[X1,V1],[X2,V2]=Two|Rest]) ->
    [[X2-X1,V1]|diff([Two|Rest])];
diff([[_,V]]) -> [[0,V]].

Using the alias in the pattern, =, means we can have our cake an eat by both pulling apart the second element and keeping a reference to it, i.e. it is a bit more efficient. We could do it for the whole rest of the list after the 1st element but it becomes a bit more difficult to read:
Code:
diff([[X1,V1]|[[X2,V2]|_]=Rest]) ->
    [[X2-X1]|diff(Rest)];

Code not tested and hopefully I didn't misunderstand what you wanted.

_________________
Robert Virding, Erlang Solutions Ltd.
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niglas
Posted: Tue Feb 08, 2011 11:01 am Reply with quote
User Joined: 31 Jan 2011 Posts: 12
I think I like the second one better.

The final function I used is then:

Code:
diff([[X1,V1]|[[X2,_]|_]=Rem]) ->
    [[X2-X1]|diff(Rem)];
    diff([[_,V]]) -> [[0,V]].
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rvirding
Posted: Tue Feb 08, 2011 11:19 am Reply with quote
User Joined: 30 Aug 2006 Posts: 452 Location: Stockholm, Sweden
Sorry, a mistake crept into my code! It should be:
Code:
diff([[X1,V]|[[X2,_]|_]=Rem]) ->
    [[X2-X1,V]|diff(Rem)];
    diff([[_,V]]) -> [[0,V]].

I forgot to add the actual value not just the difference.

_________________
Robert Virding, Erlang Solutions Ltd.
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niglas
Posted: Tue Feb 08, 2011 11:46 am Reply with quote
User Joined: 31 Jan 2011 Posts: 12
rvirding wrote:
It should be:
Code:
diff([[X1,V]|[[X2,_]|_]=Rem]) ->
    [[X2-X1,V]|diff(Rem)];
    diff([[_,V]]) -> [[0,V]].


Yeah, I made a typo too. It should have been what you now corrected it to. That's what I am using right now. Thanks!
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Posted: Wed Aug 15, 2012 6:30 am Reply with quote
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Posted: Wed Aug 15, 2012 6:30 am Reply with quote
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